The magnetic field of an electromagnetic wave is given by
= 1.6 × 10 −6 cos(2 × 107z + 6 × 1015t)
The associated electric field will be
(a) 
= 4.8 × 102 cos(2 × 107z + 6 × 1015t)
(b) 
= 4.8 × 102 cos(2 × 107z − 6 × 1015t) 
(c) 
= 4.8 × 102 cos(2 × 107z − 6 ×1015t)
(d) 
= 4.8 × 102 cos(2 × 107z + 6 × 1015t) 
= 1.6 × 10 −6 cos(2 × 107z + 6 × 1015t) = 4.8 × 102 cos(2 × 107z + 6 × 1015t) = 4.8 × 102 cos(2 × 107z − 6 × 1015t) = 4.8 × 102 cos(2 × 107z − 6 ×1015t) = 4.8 × 102 cos(2 × 107z + 6 × 1015t) Question ID - 1 | SaraNextGen Top Answer The magnetic field of an electromagnetic wave is given by
= 1.6 × 10 −6 cos(2 × 107z + 6 × 1015t)
The associated electric field will be
(a) = 4.8 × 102 cos(2 × 107z + 6 × 1015t)
(b) = 4.8 × 102 cos(2 × 107z − 6 × 1015t)
(c) = 4.8 × 102 cos(2 × 107z − 6 ×1015t)
(d) = 4.8 × 102 cos(2 × 107z + 6 × 1015t)
The magnetic field of an electromagnetic wave is given by
= 1.6 × 10 −6 cos(2 × 107z + 6 × 1015t)
The associated electric field will be
(a) = 4.8 × 102 cos(2 × 107z + 6 × 1015t)
(b) = 4.8 × 102 cos(2 × 107z − 6 × 1015t)
(c) = 4.8 × 102 cos(2 × 107z − 6 ×1015t)
(d) = 4.8 × 102 cos(2 × 107z + 6 × 1015t)
Amplitude of electric field, E = B0C
= 1.6 × 10 −6 × 
× 3 × 108
= 4.8 × 102
V/m
Also 
× 
is along 
(the direction of propagation)
⇒ 
= 4.8 × 102 cos(2 × 107z + 6 × 1015t)