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Taking the wavelength of first Balmer line in hydrogen spectrum (n = 3 to n = 2) as 660 nm, the wavelength of the 2nd Balmer line (n = 4 to n = 2) will be:

(a)

889.2 nm

(b)

488.9 nm

(c)

388.9 nm

(d)

642.7 nm


Question ID - 51235 | Toppr Answer

Taking the wavelength of first Balmer line in hydrogen spectrum (n = 3 to n = 2) as 660 nm, the wavelength of the 2nd Balmer line (n = 4 to n = 2) will be:

(a)

889.2 nm

(b)

488.9 nm

(c)

388.9 nm

(d)

642.7 nm

1 Answer - 5876 Votes

3537

Answer Key : (b) -

 

 

 

 =

= 489 nm



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