The electric field of light wave is given as 
This Light falls on a metal plate of work function 2eV. The stopping potential of the photoelectrons is : Given, E (in eV) = 
(a)
0.48 V
(b)
2.48 V
(c)
0.72 V
(d)
2.0 V
The electric field of light wave is given as This Light falls on a metal plate of work function 2eV. The stopping potential of the photoelectrons is : Given, E (in eV) =
(a)
0.48 V
(b)
2.48 V
(c)
0.72 V
(d)
2.0 V
Question ID - 51245 | SaraNextGen Top Answer
The electric field of light wave is given as This Light falls on a metal plate of work function 2eV. The stopping potential of the photoelectrons is : Given, E (in eV) =
(a)
0.48 V
(b)
2.48 V
(c)
0.72 V
(d)
2.0 V
|
The electric field of light wave is given as |
|||
|
(a) |
0.48 V |
(b) |
2.48 V |
|
(c) |
0.72 V |
(d) |
2.0 V |
1 Answer
127 votes
m
=6
127