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The electric field of light wave is given as       This Light falls on a metal plate of work function 2eV. The stopping potential of the photoelectrons is : Given, E (in eV) =  

(a)

0.48 V

(b)

2.48 V

(c)

0.72 V

(d)

2.0 V


Question ID - 51245 | Toppr Answer

The electric field of light wave is given as       This Light falls on a metal plate of work function 2eV. The stopping potential of the photoelectrons is : Given, E (in eV) =  

(a)

0.48 V

(b)

2.48 V

(c)

0.72 V

(d)

2.0 V

1 Answer - 5876 Votes

3537

Answer Key : (a) -

m

=6

E =

Kmax = E  

= 0.48 eV



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