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50 W/m2 energy density of sunlight is normally incident on the surface of a solar panel.  Some part of incident energy (25%) is reflected from the surface and the rest is absorbed.  The force exerted on 1m2 surface area will be close to (c=3 108 m/s):

(a)

20 108 N

(b)

35  108 N

(c)

15  108 N

(d)

10 108 N



Question ID - 51274 | SaraNextGen Top Answer

50 W/m2 energy density of sunlight is normally incident on the surface of a solar panel.  Some part of incident energy (25%) is reflected from the surface and the rest is absorbed.  The force exerted on 1m2 surface area will be close to (c=3 108 m/s):

(a)

20 108 N

(b)

35  108 N

(c)

15  108 N

(d)

10 108 N

1 Answer
127 votes
Answer Key / Explanation : (a) -

p=  and pressure =I/c

∴  +  ⇒   for one photon

∴    =pressure

But =50 W/m2

       =Pressure

∴    Fn=  =20 10−8 N

127 votes


127