A He+ ion in its first excited state. Its ionization energy is:
(a)
13.60 eV
(b)
6.04 eV
(c)
48.36 eV
(d)
54.40 eV
A He+ ion in its first excited state. Its ionization energy is:
(a)
13.60 eV
(b)
6.04 eV
(c)
48.36 eV
(d)
54.40 eV
Question ID - 51286 | SaraNextGen Top Answer
A He+ ion in its first excited state. Its ionization energy is:
(a)
13.60 eV
(b)
6.04 eV
(c)
48.36 eV
(d)
54.40 eV
|
A He+ ion in its first excited state. Its ionization energy is: |
|||
|
(a) |
13.60 eV |
(b) |
6.04 eV |
|
(c) |
48.36 eV |
(d) |
54.40 eV |
1 Answer
127 votes
Answer Key / Explanation : (a) -
En: 
=
=−E0
To ionize it E0 energy must be supplied.
∴ E0=13.6 eV.
127 votes
Answer Link
127