A particle of mass ‘m’ is moving with speed ‘2v’ and collides ‘v’ in the same direction. After collision, the first mass is stopped completely while the second one splits into two particles each of mass ‘m’, which move at an angle 45
with respect to the original direction. The speed of each of the moving particle will be
(a)
v/(2
)
(b)
(c)
(d)
2
A particle of mass ‘m’ is moving with speed ‘2v’ and collides ‘v’ in the same direction. After collision, the first mass is stopped completely while the second one splits into two particles each of mass ‘m’, which move at an angle 45 with respect to the original direction. The speed of each of the moving particle will be
(a)
v/(2 )
(b)
(c)
(d)
2
Question ID - 51309 | SaraNextGen Top Answer
A particle of mass ‘m’ is moving with speed ‘2v’ and collides ‘v’ in the same direction. After collision, the first mass is stopped completely while the second one splits into two particles each of mass ‘m’, which move at an angle 45 with respect to the original direction. The speed of each of the moving particle will be
(a)
v/(2 )
(b)
(c)
(d)
2
|
A particle of mass ‘m’ is moving with speed ‘2v’ and collides ‘v’ in the same direction. After collision, the first mass is stopped completely while the second one splits into two particles each of mass ‘m’, which move at an angle 45 |
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|
(a) |
v/(2 |
(b) |
|
|
(c) |
|
(d) |
2 |
Initial momentum p1=2mv+2mv=4v
Let v’ be the speed of 1 particle
∴ 2
=4mv
⇒ v’ = 2
v