A thin disc of mass M and radius R has mass per unit area
(r) = kr2 where r is the distance from its centre. Its moment of inertia about an axis going through its centre of mass and perpendicular to its plane is :
(a)
(b)
(c)
(d)
A thin disc of mass M and radius R has mass per unit area (r) = kr2 where r is the distance from its centre. Its moment of inertia about an axis going through its centre of mass and perpendicular to its plane is :
(a)
(b)
(c)
(d)
Question ID - 51340 | SaraNextGen Top Answer
A thin disc of mass M and radius R has mass per unit area (r) = kr2 where r is the distance from its centre. Its moment of inertia about an axis going through its centre of mass and perpendicular to its plane is :
(a)
(b)
(c)
(d)
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A thin disc of mass M and radius R has mass per unit area |
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(a) |
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(b) |
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(c) |
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(d) |
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1 Answer
127 votes
Answer Key / Explanation : (d) -
Surface mass density (
Mass of disc M= 
2
=2
=
moment of interia about the axis of the disc.
I= 
= 
=
=
=
dr=
=
M
127 votes
Answer Link
127