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A square loop is carrying a steady current l and the magnitude of its magnetic dipole moment is m.  If this square loop is changed to a circular loop and it carries the same current, the magnitude of the  magnetic dipole moment of circular loop will be :

(a)

(b)

(c)

(d)


Question ID - 51400 :-

A square loop is carrying a steady current l and the magnitude of its magnetic dipole moment is m.  If this square loop is changed to a circular loop and it carries the same current, the magnitude of the  magnetic dipole moment of circular loop will be :

(a)

(b)

(c)

(d)

1 Answer
5876 Votes
3537

Answer Key : (b) -

2 ⇒ r =

m=(l)

=(l)

=(l)

=

=



Next Question :

The average of marks of 13 papers is 40. The average of marks of the first 7 papers is 42 and that of the last 7 papers is 35. What are the marks of the seventh paper?

(a) 17                               (b) 18                                   (c) 19                           (d) 20


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