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A square loop is carrying a steady current l and the magnitude of its magnetic dipole moment is m.  If this square loop is changed to a circular loop and it carries the same current, the magnitude of the  magnetic dipole moment of circular loop will be :

(a)

(b)

(c)

(d)



Question ID - 51400 | SaraNextGen Top Answer

A square loop is carrying a steady current l and the magnitude of its magnetic dipole moment is m.  If this square loop is changed to a circular loop and it carries the same current, the magnitude of the  magnetic dipole moment of circular loop will be :

(a)

(b)

(c)

(d)

1 Answer
127 votes
Answer Key / Explanation : (b) -

2 ⇒ r =

m=(l)

=(l)

=(l)

=

=

127 votes


127