10 years ago, the average age of a family of 4 members was 24 years. Since then, two children having been born, still the average age of the family is the same today. If the two children differ in age by 2 years, find the present age of the younger child.
(a) 2 yrs. (b) 3 yrs. (c) 5 yrs. (d) 6 yrs.
Question ID - 51418 | SaraNextGen Top Answer 10 years ago, the average age of a family of 4 members was 24 years. Since then, two children having been born, still the average age of the family is the same today. If the two children differ in age by 2 years, find the present age of the younger child.
(a) 2 yrs. (b) 3 yrs. (c) 5 yrs. (d) 6 yrs.
10 years ago, the average age of a family of 4 members was 24 years. Since then, two children having been born, still the average age of the family is the same today. If the two children differ in age by 2 years, find the present age of the younger child.
(a) 2 yrs. (b) 3 yrs. (c) 5 yrs. (d) 6 yrs.
Total age of 4 members, 10 yrs. ago = 
yrs. = 96 yrs.
Total age of 4 members now = 
yrs. = 136 yrs.
Total age of 6 members now = 
yrs. = 144 yrs.
Sum of the ages of 2 children = 144
136 = 8 yrs.
Let the age of the younger child be 
yrs.
Then, age of elder child = 
yrs.
So, 
∴ Age of the younger child = 3 yrs.