10 years ago, the average age of a family of 4 members was 24 years. Since then, two children having been born, still the average age of the family is the same today. If the two children differ in age by 2 years, find the present age of the younger child.

(a) 2 yrs. (b) 3 yrs. (c) 5 yrs. (d) 6 yrs.

10 years ago, the average age of a family of 4 members was 24 years. Since then, two children having been born, still the average age of the family is the same today. If the two children differ in age by 2 years, find the present age of the younger child.

(a) 2 yrs. (b) 3 yrs. (c) 5 yrs. (d) 6 yrs.

1 Answer

127 votes

Total age of 4 members, 10 yrs. ago = yrs. = 96 yrs.

Total age of 4 members now = yrs. = 136 yrs.

Total age of 6 members now = yrs. = 144 yrs.

Sum of the ages of 2 children = 144 136 = 8 yrs.

Let the age of the younger child be yrs.

Then, age of elder child = yrs.

So,

∴ Age of the younger child = 3 yrs.

127 votes

127