# 10 years ago, the average age of a family of 4 members was 24 years. Since then, two children having been born, still the average age of the family is the same today. If the two children differ in age by 2 years, find the present age of the younger child. (a) 2 yrs.                                  (b) 3 yrs.                             (c) 5 yrs.                     (d) 6 yrs.

## Question ID - 51418 | SaraNextGen Top Answer 10 years ago, the average age of a family of 4 members was 24 years. Since then, two children having been born, still the average age of the family is the same today. If the two children differ in age by 2 years, find the present age of the younger child. (a) 2 yrs.                                  (b) 3 yrs.                             (c) 5 yrs.                     (d) 6 yrs.

Answer Key / Explanation : (b) -

Total age of 4 members, 10 yrs. ago =  yrs. = 96 yrs.

Total age of 4 members now = yrs. = 136 yrs.

Total age of 6 members now =  yrs. = 144 yrs.

Sum of the ages of 2 children = 144 136 = 8 yrs.

Let the age of the younger child be  yrs.

Then, age of elder child =  yrs.

So,

∴  Age of the younger child = 3 yrs.