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The stopping potential V0 (in volt) as a function of frequency (v) for a sodium emitter, is shown in the figure. The work function of sodium, from the data plotted in the figure, will be: (Given: Planck’s constant) (h) = 6.63 × 10–34 Js, electron charge e = 1.6 × 10–19 C)

                               

a)

1.95 eV

b)

2.12 eV

c)

1.82 eV

d)

1.66 eV



Question ID - 51464 | SaraNextGen Top Answer

The stopping potential V0 (in volt) as a function of frequency (v) for a sodium emitter, is shown in the figure. The work function of sodium, from the data plotted in the figure, will be: (Given: Planck’s constant) (h) = 6.63 × 10–34 Js, electron charge e = 1.6 × 10–19 C)

                               

a)

1.95 eV

b)

2.12 eV

c)

1.82 eV

d)

1.66 eV

1 Answer
127 votes
Answer Key / Explanation : (d) -

   

       =  h × 4 × 1014 Hz = 1.654 eV

 ⇒    1.66 eV

127 votes


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