If the sum of the distances of a point from two perpendicular lines a plane is 1, then its locus is |
|||
a) |
Square |
b) |
Circle |
c) |
Straight line |
d) |
Two intersecting lines |
If the sum of the distances of a point from two perpendicular lines a plane is 1, then its locus is |
|||
a) |
Square |
b) |
Circle |
c) |
Straight line |
d) |
Two intersecting lines |
(a)
Let the two perpendicular lines be the coordinate axes. Let be the point, sum of whose distance from two axes is 1. Then we must have
or
These are the four lines . Any two adjacent sides are perpendicular to each other. Also, each line is equidistant from origin. Therefore, figure formed is a square
The distance between the two lines represented by the equation |
|||||||
a) |
8/5 |
b) |
6/5 |
c) |
11/5 |
d) |
None of these |
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