A force (where is a positive constant) acts on a particle moving in the -plane. Starting from the origin, the particle is taken along the positive -axis to the point ( ) and then parallel to the -axis to the point ( ). The total work done by the force on the particles is |
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a) |
b) |
c) |
d) |

A force (where is a positive constant) acts on a particle moving in the -plane. Starting from the origin, the particle is taken along the positive -axis to the point ( ) and then parallel to the -axis to the point ( ). The total work done by the force on the particles is |
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a) |
b) |
c) |
d) |

1 Answer

127 votes

While moving from (0,0) to ( ) Along positive -axis, ., force is in negative - direction while displacement is in positive -direction Because force is perpendicular to displacement Then particle moves from ( ) to ( ) along a line parallel to -axis during this The first component of force, will not contribute any work because this component is along negative -direction while displacement is in positive -direction to . The second component of force will perform negative work So net work done on the particle |

127 votes

127