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The ground state energy of hydrogen atom is −13.6 eV. The energy of second excited state He+ ion in eV is :

(a)

−6.04

(b)

−27.2

(c)

−54.4

(d)

−3.4


Question ID - 52204 | Toppr Answer

The ground state energy of hydrogen atom is −13.6 eV. The energy of second excited state He+ ion in eV is :

(a)

−6.04

(b)

−27.2

(c)

−54.4

(d)

−3.4

1 Answer - 5876 Votes

3537

Answer Key : (a) -

(E)nth  = (EGND)H.

E3rd(He+) =(−13.6eV). = −6.04eV.



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