Given the equilibrium constant: KC of the reaction:
Cu(s) + 2Ag+(aq) 
Cu2+(aq) + 2Ag(s) is 10 × 1015, calculate the 
of this reaction at 298 K 
a.
0.04736 V
b.
0.4736 V
c.
0.4736 mV
d.
0.04736 mV
Cu2+(aq) + 2Ag(s) is 10 × 1015, calculate the of this reaction at 298 K a.
0.04736 V
b.
0.4736 V
c.
0.4736 mV
d.
0.04736 mV
Question ID - 52250 | SaraNextGen Top Answer Given the equilibrium constant: KC of the reaction:
Cu(s) + 2Ag+(aq) Cu2+(aq) + 2Ag(s) is 10 × 1015, calculate the of this reaction at 298 K
a.
0.04736 V
b.
0.4736 V
c.
0.4736 mV
d.
0.04736 mV
Given the equilibrium constant: KC of the reaction:
Cu(s) + 2Ag+(aq) Cu2+(aq) + 2Ag(s) is 10 × 1015, calculate the of this reaction at 298 K
|
a. |
0.04736 V |
b. |
0.4736 V |
|
c. |
0.4736 mV |
d. |
0.04736 mV |
1 Answer
127 votes
Answer Key / Explanation : (b) -
Ecell = 
– 
logQ
At equilibrium
log1016
= 0.059 × 8
= 0.472 V
127 votes
Answer Link
127