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Given the equilibrium constant: KC of the reaction:

Cu(s) + 2Ag+(aq) Cu2+(aq) + 2Ag(s) is 10 × 1015, calculate the  of this reaction at 298 K  

a.

0.04736 V

b.

0.4736 V

c.

0.4736 mV

d.

0.04736 mV


Question ID - 52250 :-

Given the equilibrium constant: KC of the reaction:

Cu(s) + 2Ag+(aq) Cu2+(aq) + 2Ag(s) is 10 × 1015, calculate the  of this reaction at 298 K  

a.

0.04736 V

b.

0.4736 V

c.

0.4736 mV

d.

0.04736 mV

1 Answer
5876 Votes
3537

Answer Key : (b) -

Ecell =  –  logQ

At equilibrium

  log1016

= 0.059 × 8

= 0.472 V



Next Question :

The hydride that is NOT electron deficient is:-

a.

B2H6

b.

AlH3

c.

SiH4

d.

GaH3


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