Two solids dissociate as follows
A(s) 
B(g) + C (g) ; 
= x atm2
D(s) 
C(g) + E (g) ; 
= y atm2
The total pressure when both the solids dissociate simultaneously is
a.
x2 + y2 atm
b.
x2 + y2 atm
c.
2(
)atm
d.
atm
B(g) + C (g) ; = x atm2 C(g) + E (g) ; = y atm2a.
x2 + y2 atm
b.
x2 + y2 atm
c.
2()atm
d.
atm
Question ID - 52336 | SaraNextGen Top Answer Two solids dissociate as follows
A(s) B(g) + C (g) ; = x atm2
D(s) C(g) + E (g) ; = y atm2
The total pressure when both the solids dissociate simultaneously is
a.
x2 + y2 atm
b.
x2 + y2 atm
c.
2()atm
d.
atm
Two solids dissociate as follows
A(s) B(g) + C (g) ; = x atm2
D(s) C(g) + E (g) ; = y atm2
The total pressure when both the solids dissociate simultaneously is
|
a. |
x2 + y2 atm |
b. |
x2 + y2 atm |
|
c. |
2( |
d. |
|
1 Answer
127 votes
Answer Key / Explanation : (c) -
A(s) 
B(g) + C (g) ; 
= x= PB PC
P1 P1 x = P1(P1+P2) … (1)
D(s) 
C(g) + E (g) ; 
= y = PC. PB
P2 P2 y = (P1+P2)( P2) … (2)
Adding (1) and (2)
x+y = 
Now total pressure
= PC + PB + PE
= (P1 + P2 )+ P1 + P2=2(P1 + P2 )
= 2(
)
127 votes
Answer Link
127