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For a reaction consider the plot of ln k versus 1/T given in the figure. If the rate constant of this reaction at 400 K is 10−5 s−1, then the rate constant at 500 K is  

(a)

2×10−4 s−1

(b)

10−4 s−1

(c)

10−6 s−1

(d)

4×104S1



Question ID - 52412 | SaraNextGen Top Answer

For a reaction consider the plot of ln k versus 1/T given in the figure. If the rate constant of this reaction at 400 K is 10−5 s−1, then the rate constant at 500 K is  

(a)

2×10−4 s−1

(b)

10−4 s−1

(c)

10−6 s−1

(d)

4×104S1

1 Answer
127 votes
Answer Key / Explanation : (b) -

ln=

2.303 = 4606

2=104 S1

127 votes


127