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For the reaction 2A + B → C, the values of initial rate at different reactant concentrations are given in the table below. The rate law for the reaction is

[A] (mol L−1)

[B](mol L−1)

Initial rate

(mol L−1s−1)

0.05

0.05

0.045

0.10

0.05

0.090

0.20

0.10

0.72

(a)

Rate = k[A]2[B]2

(b)

Rate = k[A][B]

(c)

Rate = k[A]2[B]

(d)

Rate = k[A][B]2



Question ID - 52441 | SaraNextGen Top Answer

For the reaction 2A + B → C, the values of initial rate at different reactant concentrations are given in the table below. The rate law for the reaction is

[A] (mol L−1)

[B](mol L−1)

Initial rate

(mol L−1s−1)

0.05

0.05

0.045

0.10

0.05

0.090

0.20

0.10

0.72

(a)

Rate = k[A]2[B]2

(b)

Rate = k[A][B]

(c)

Rate = k[A]2[B]

(d)

Rate = k[A][B]2

1 Answer
127 votes
Answer Key / Explanation : (d) -

 2A + B  → C

Rate = k[A]x[B]y

Exp-1, 0.045 = k[0.05]x [0.05]y                  …(i)

Exp-2, 0.090 = k[0.1]x[0.05]y               …(ii)

Exp-3, 0.72  = k[0.2]x [0.1]y                    …(iii)

Divide equation (i) by equation (ii)

 =  ⇒x=1

Divide equation (i) by equation (iii)

=

=  ⇒ y = 2

Rate law = k[A]1[B]2.

127 votes


127