5 moles of an ideal gas at 100 K are allowed to undergo reversible compression till its temperature becomes 200 K. If CV = 28 J K–1 mol–1, calculate 
U and 
pV for this process.(R = 8.0 J K–1 mol–1)
(a)
U = 14 kJ; 
(pV) = 18 kJ
(b)
U = 2.8 kJ; 
(pV) = 0.8 kJ
(c)
U = 14 J; 
(pV) = 0.8 kJ
(d)
U = 14 kJ; 
(pV) = 4 kJ
5 moles of an ideal gas at 100 K are allowed to undergo reversible compression till its temperature becomes 200 K. If CV = 28 J K–1 mol–1, calculate U and pV for this process.(R = 8.0 J K–1 mol–1)
(a)
U = 14 kJ; (pV) = 18 kJ
(b)
U = 2.8 kJ; (pV) = 0.8 kJ
(c)
U = 14 J; (pV) = 0.8 kJ
(d)
U = 14 kJ; (pV) = 4 kJ
Question ID - 52524 | SaraNextGen Top Answer
5 moles of an ideal gas at 100 K are allowed to undergo reversible compression till its temperature becomes 200 K. If CV = 28 J K–1 mol–1, calculate U and pV for this process.(R = 8.0 J K–1 mol–1)
(a)
U = 14 kJ; (pV) = 18 kJ
(b)
U = 2.8 kJ; (pV) = 0.8 kJ
(c)
U = 14 J; (pV) = 0.8 kJ
(d)
U = 14 kJ; (pV) = 4 kJ
|
5 moles of an ideal gas at 100 K are allowed to undergo reversible compression till its temperature becomes 200 K. If CV = 28 J K–1 mol–1, calculate |
|||
|
(a) |
|
(b) |
|
|
(c) |
|
(d) |
|
1 Answer
127 votes
Answer Key / Explanation : (d) -
ΔU = n cvm ΔT=5
28
100
=14kJ
(PV)=nR(T2−T1)
= 5 × 8 × 100
= 4 kJ
127 votes
Answer Link
127