The standard Gibbs energy for the given cell reaction in kJ mol−1 at 298 K is
Zn(s) +Cu2+(aq)
Zn2+(aq)+ Cu(s), E° = 2 V at 298 K (Faraday’s constant, F = 96000 C mol−1)
(a)
192
(b)
384
(c)
−384
(d)
−192
The standard Gibbs energy for the given cell reaction in kJ mol−1 at 298 K is
Zn(s) +Cu2+(aq)Zn2+(aq)+ Cu(s), E° = 2 V at 298 K (Faraday’s constant, F = 96000 C mol−1)
(a)
192
(b)
384
(c)
−384
(d)
−192
Question ID - 52566 | SaraNextGen Top Answer
The standard Gibbs energy for the given cell reaction in kJ mol−1 at 298 K is
Zn(s) +Cu2+(aq)Zn2+(aq)+ Cu(s), E° = 2 V at 298 K (Faraday’s constant, F = 96000 C mol−1)
(a)
192
(b)
384
(c)
−384
(d)
−192
|
The standard Gibbs energy for the given cell reaction in kJ mol−1 at 298 K is Zn(s) +Cu2+(aq) |
|||
|
(a) |
192 |
(b) |
384 |
|
(c) |
−384 |
(d) |
−192 |
1 Answer
127 votes
G° = − nF
127