Increasing order of reactivity of the following compounds for SN 1 substitution is
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(a)
(B)<(C)<(A)<(D)
(b)
(B)<(C)<(D)<(A)
(c)
(B)<(A)<(D)<(C)
(d)
(A)<(B)<(D)<(C)
Increasing order of reactivity of the following compounds for SN 1 substitution is
(a)
(B)<(C)<(A)<(D)
(b)
(B)<(C)<(D)<(A)
(c)
(B)<(A)<(D)<(C)
(d)
(A)<(B)<(D)<(C)
Question ID - 52637 | SaraNextGen Top Answer
Increasing order of reactivity of the following compounds for SN 1 substitution is
(a)
(B)<(C)<(A)<(D)
(b)
(B)<(C)<(D)<(A)
(c)
(B)<(A)<(D)<(C)
(d)
(A)<(B)<(D)<(C)
|
Increasing order of reactivity of the following compounds for SN 1 substitution is
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|
(a) |
(B)<(C)<(A)<(D) |
(b) |
(B)<(C)<(D)<(A) |
|
(c) |
(B)<(A)<(D)<(C) |
(d) |
(A)<(B)<(D)<(C) |
1 Answer
127 votes
Answer Key / Explanation : (c) -
SN1 reaction proceeds via formation of carbocation
On comparing (A) and (B), in (A) there is formation of tertiary carbocation 
after rearrangement while (B) is primary. So, (B)<(A)<(D)<(C)
127 votes
Answer Link
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