At a given temperature T, gases Ne, Ar, Xe and Kr are found to deviate from ideal gas behavior. Their equation of state is given as P=
at T
Here, b is the Vander Waal’s constant. Which gas will exhibit steepest increase in the plot of Z (compression factor) vs P?
(a)
Kr
(b)
Ar
(c)
Xe
(d)
Ne
At a given temperature T, gases Ne, Ar, Xe and Kr are found to deviate from ideal gas behavior. Their equation of state is given as P= at T
Here, b is the Vander Waal’s constant. Which gas will exhibit steepest increase in the plot of Z (compression factor) vs P?
(a)
Kr
(b)
Ar
(c)
Xe
(d)
Ne
Question ID - 52658 | SaraNextGen Top Answer
At a given temperature T, gases Ne, Ar, Xe and Kr are found to deviate from ideal gas behavior. Their equation of state is given as P= at T
Here, b is the Vander Waal’s constant. Which gas will exhibit steepest increase in the plot of Z (compression factor) vs P?
(a)
Kr
(b)
Ar
(c)
Xe
(d)
Ne
|
At a given temperature T, gases Ne, Ar, Xe and Kr are found to deviate from ideal gas behavior. Their equation of state is given as P= Here, b is the Vander Waal’s constant. Which gas will exhibit steepest increase in the plot of Z (compression factor) vs P? |
|||
|
(a) |
Kr |
(b) |
Ar |
|
(c) |
Xe |
(d) |
Ne |
1 Answer
127 votes
Answer Key / Explanation : (c) -
P=
⇒PVm−Pb=RT
⇒
=1+
⇒Z=1+
Slope of Z vs curve (straight line) = 
∴ Higher the value of b, more steep will be the curve and b 
size of gas molecules
127 votes
Answer Link
127