Consider the following statements
(A) The PH of a mixture containing 400 ml of 0.1M H2SO4 and 400ml of 0.1M NaOH will be approximately 1.3.
(B) Ionic product of water is temperature dependent
(C)A monobasic acid with 
=10 −5 has a pH=5. The degree of dissociation of this acid is 50%
(D) The Le Chatelier’s principle is not applicable to common ion effect.
The correct statements are
(a)
(A), (B) and (D)
(b)
(B) and (C)
(c)
(A) and (B)
(d)
(A), (B) and (C)
Consider the following statements
(A) The PH of a mixture containing 400 ml of 0.1M H2SO4 and 400ml of 0.1M NaOH will be approximately 1.3.
(B) Ionic product of water is temperature dependent
(C)A monobasic acid with =10 −5 has a pH=5. The degree of dissociation of this acid is 50%
(D) The Le Chatelier’s principle is not applicable to common ion effect.
The correct statements are
(a)
(A), (B) and (D)
(b)
(B) and (C)
(c)
(A) and (B)
(d)
(A), (B) and (C)
Question ID - 52682 | SaraNextGen Top Answer
Consider the following statements
(A) The PH of a mixture containing 400 ml of 0.1M H2SO4 and 400ml of 0.1M NaOH will be approximately 1.3.
(B) Ionic product of water is temperature dependent
(C)A monobasic acid with =10 −5 has a pH=5. The degree of dissociation of this acid is 50%
(D) The Le Chatelier’s principle is not applicable to common ion effect.
The correct statements are
(a)
(A), (B) and (D)
(b)
(B) and (C)
(c)
(A) and (B)
(d)
(A), (B) and (C)
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Consider the following statements (A) The PH of a mixture containing 400 ml of 0.1M H2SO4 and 400ml of 0.1M NaOH will be approximately 1.3. (B) Ionic product of water is temperature dependent (C)A monobasic acid with (D) The Le Chatelier’s principle is not applicable to common ion effect. The correct statements are |
|||
|
(a) |
(A), (B) and (D) |
(b) |
(B) and (C) |
|
(c) |
(A) and (B) |
(d) |
(A), (B) and (C) |
(A) H2SO4 + NaOH→ NaHSO4 + H2O
Initial moles 0.04 0.04
0 0 0.04 0.04
NaHSO4→Na+ + 
=
=0.05M; PH = 1.3
(B) Ionic product of water increases with increase of temperature because ionization of water is endothermic.
(C) HA 
+ 
C(1−
) C
C
PH= 5 & 
= 10 −5
10 −5=
; C= 2 × 10 −5 and 