The isoelectronic set of ions is :

(a)

N^{3 −} ,L^{i+} ,Mg^{2+} and O^{2 −}

(b)

L^{i+} ,N^{a+} ,O^{2 −} and F^{ −}

(c)

N^{3+} ,O^{2 −} ,F^{ −} and N^{a+}

(d)

F^{ − } ,L^{i+ } ,N^{a+} and Mg^{2+}

Question ID - 52708 | Toppr Answer
The isoelectronic set of ions is :

(a)

N^{3 −} ,L^{i+} ,Mg^{2+} and O^{2 −}

(b)

L^{i+} ,N^{a+} ,O^{2 −} and F^{ −}

(c)

N^{3+} ,O^{2 −} ,F^{ −} and N^{a+}

(d)

F^{ − } ,L^{i+ } ,N^{a+} and Mg^{2+}

1 Answer - 5876 Votes

3537

Answer Key : (c) -

Atomic numbers of N, O, F and Na are 7, 8, 9 and 11 respectively .Therefore, total number of electrons in each of N^{3−} , O^{2−} , F^{−} and Na^{+} is 10 and hence they are isoelectronic.

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