If sum of the distance of a point from two perpendicular lines in a plane is 1, then its locus is |
|||
a) |
A square |
b) |
A circle |
c) |
A straight line |
d) |
Two intersecting lines |
If sum of the distance of a point from two perpendicular lines in a plane is 1, then its locus is |
|||
a) |
A square |
b) |
A circle |
c) |
A straight line |
d) |
Two intersecting lines |
(a)
Let the two perpendicular lines be taken as the coordinate axes. If be any point on the locus, then according to the given condition
. Hence, the locus of
is
. This consists of four line segments enclosing
square as shown in the figure below
|
|||||||
a) |
7 |
b) |
5 |
c) |
4 |
d) |
6 |
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