The age of father is 3 years more than 3 times the son’s age. 3 years hence, the age of the father will be 10 years more than twice the age of the son. The present age of father and son are respectively (in years) |
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a) |
10, 33 |
b) |
33, 9 |
c) |
33, 10 |
d) |
None of these |

The age of father is 3 years more than 3 times the son’s age. 3 years hence, the age of the father will be 10 years more than twice the age of the son. The present age of father and son are respectively (in years) |
|||||||

a) |
10, 33 |
b) |
33, 9 |
c) |
33, 10 |
d) |
None of these |

1 Answer

127 votes

Let the present age of father be years and the present age of son be years.

∴ According to question, we have

…(i)

Again, 3 years hence, age of father= years and that of son’s = (years.

∴ or …(ii)

Solving (i) and (ii), we get and

∴ Age of father=33 years and age of son=10years

**Alternative Method:**

Let son’s present age = years then father’s age = (3years

∴ (age of son)

Also, father’s present age is 3years.

127 votes

127