# A bullet of mass is fired with a velocity of 50 at an angle with the horizontal. At the highest point of its trajectory, it collides had on with a bob of massless string of length m and gets embedded in the bob. After the collision, the string moves to an angle of 120 . What is the angle  a) b) c) d) ## Question ID - 53939 :- A bullet of mass is fired with a velocity of 50 at an angle with the horizontal. At the highest point of its trajectory, it collides had on with a bob of massless string of length m and gets embedded in the bob. After the collision, the string moves to an angle of 120 . What is the angle  a) b) c) d) 3537

(a)

Velocity of bullet at highest point of its trajectory = 50 in horizontal direction.

As bullet of mass collides with pendulum bob of mass 3 and two stick together, their common velocity As now under this velocity pendulum bob goes up to an angel 120 , hence  or Comparing two answer of , we get or Next Question :
 If the torque is zero, what will be the value of angular momentum? a) Constant in magnitude but changing is direction b) Changing in magnitude but constant in direction c) Constant on both magnitude and direction d) Zero 