Last Updated On [03-11-2023]
A bullet of mass 
is fired with a velocity of 50 
at an angle 
with the horizontal. At the highest point of its trajectory, it collides had on with a bob of massless string of length 
m and gets embedded in the bob. After the collision, the string moves to an angle of 120
. What is the angle 
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a) |
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b) |
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c) |
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d) |
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Question ID - 53939 :- A bullet of mass is fired with a velocity of 50 at an angle with the horizontal. At the highest point of its trajectory, it collides had on with a bob of massless string of length m and gets embedded in the bob. After the collision, the string moves to an angle of 120 . What is the angle
a)
b)
c)
d)
A bullet of mass is fired with a velocity of 50 at an angle with the horizontal. At the highest point of its trajectory, it collides had on with a bob of massless string of length m and gets embedded in the bob. After the collision, the string moves to an angle of 120 . What is the angle
|
a) |
|
b) |
|
c) |
|
d) |
|
(a)
Velocity of bullet at highest point of its trajectory = 50 
in horizontal direction.
As bullet of mass 
collides with pendulum bob of mass 3
and two stick together, their common velocity
As now under this velocity 
pendulum bob goes up to an angel 120
, hence
or 
Comparing two answer of 
, we get
or
Next Question :
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If the torque is zero, what will be the value of angular momentum? |
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|
a) |
Constant in magnitude but changing is direction |
b) |
Changing in magnitude but constant in direction |
c) |
Constant on both magnitude and direction |
d) |
Zero |
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