# Consider the triangle having vertices  and . Also  min  means  when  is least;  when  is least and so on. From this we can say   Let  be the region consisting of all those points  inside  which satisfy  min . where  denotes the distance from the point to the corresponding line. Then the area of the region  is   a)  sq. units b)  sq. units c)  sq. units d)  sq. units

## Question ID - 55429 | SaraNextGen Top Answer Consider the triangle having vertices  and . Also  min  means  when  is least;  when  is least and so on. From this we can say   Let  be the region consisting of all those points  inside  which satisfy  min . where  denotes the distance from the point to the corresponding line. Then the area of the region  is   a)  sq. units b)  sq. units c)  sq. units d)  sq. units

Answer Key / Explanation : (d) -

(d)

And

When  is equidistant from  and , or  lies on angle bisector of lines  and . Hence, when , point  is nearer to  than  or lies below bisector of  and . Similarly, when  is nearer to  than , or lies below bisector of  and . Therefore, the required area is equal to the area of

Now,

Hence, triangle is equilateral. Then  coincides with centroid, which is

Therefore, area of  is  sq. units