Consider the triangle having vertices 
and 
. Also 
min 
means 
when 
is least; 
when 
is least and so on. From this we can say 
Let 
be the region consisting of all those points 
inside 
which satisfy 
min 
. where 
denotes the distance from the point to the corresponding line. Then the area of the region 
is
a)
sq. units
b)
sq. units
c)
sq. units
d)
sq. units
Consider the triangle having vertices and . Also min means when is least; when is least and so on. From this we can say
Let be the region consisting of all those points inside which satisfy min . where denotes the distance from the point to the corresponding line. Then the area of the region is
a)
sq. units
b)
sq. units
c)
sq. units
d)
sq. units
Question ID - 55429 | SaraNextGen Top Answer
Consider the triangle having vertices and . Also min means when is least; when is least and so on. From this we can say
Let be the region consisting of all those points inside which satisfy min . where denotes the distance from the point to the corresponding line. Then the area of the region is
a)
sq. units
b)
sq. units
c)
sq. units
d)
sq. units
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Consider the triangle having vertices |
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Let |
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(d)
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And 
When 
is equidistant from 
and 
, or 
lies on angle bisector of lines 
and 
. Hence, when 
, point 
is nearer to 
than 
or lies below bisector of 
and 
. Similarly, when 
is nearer to 
than 
, or lies below bisector of 
and 
. Therefore, the required area is equal to the area of 
Now,
Hence, triangle is equilateral. Then 
coincides with centroid, which is 
Therefore, area of 
is 
sq. units