If log3=x, log5=y,log7=z, then log(9×) |
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a) |
2x+z |
b) |
x |
c) |
d) |
If log3=x, log5=y,log7=z, then log(9×) |
|||||||
a) |
2x+z |
b) |
x |
c) |
d) |
Given,
∴ log ()=log(9×
=log 9+
2 log 3+ log (
=
=