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Find the number of digits in 312×28 if log3=0.4771213 and log2=0.30103.

a)

8

b)

9

c)

10

d)

11



Question ID - 55586 | SaraNextGen Top Answer

Find the number of digits in 312×28 if log3=0.4771213 and log2=0.30103.

a)

8

b)

9

c)

10

d)

11

1 Answer
127 votes
Answer Key / Explanation : (b) -

Let

=

=5.7254556+2.40824=8.1336956

⇒ Characteristic is 8 therefore number of digits = 9

127 votes


127