A circle of constant radius passes through origin and cuts the axes of co-ordinates in points and , then the equation of the locus of the foot of perpendicular from to is |
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a) |
b) |
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c) |
d) |

A circle of constant radius passes through origin and cuts the axes of co-ordinates in points and , then the equation of the locus of the foot of perpendicular from to is |
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a) |
b) |
||

c) |
d) |

1 Answer

127 votes

**(c)**

Equation of line is

or

Points and

Also

Eliminating and we have

127 votes

127