If the equation of any two diagonals of a regular pentagon belongs to family of lines and their lengths are , then locus of centre of circle circumscribing the given pentagon (the triangles formed by these diagonals with sides of pentagon have no side common) is |
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a) |
b) |
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c) |
d) |

If the equation of any two diagonals of a regular pentagon belongs to family of lines and their lengths are , then locus of centre of circle circumscribing the given pentagon (the triangles formed by these diagonals with sides of pentagon have no side common) is |
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a) |
b) |
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c) |
d) |

1 Answer

127 votes

**(a)**

Point of intersection of diagonals lie on circumcircle

i.e. (1, 1), since

Locus is

127 votes

127