If the equation of any two diagonals of a regular pentagon belongs to family of lines 
and their lengths are 
, then locus of centre of circle circumscribing the given pentagon (the triangles formed by these diagonals with sides of pentagon have no side common) is
a)
b)
c)
d)
If the equation of any two diagonals of a regular pentagon belongs to family of lines and their lengths are , then locus of centre of circle circumscribing the given pentagon (the triangles formed by these diagonals with sides of pentagon have no side common) is
a)
b)
c)
d)
Question ID - 56048 | SaraNextGen Top Answer
If the equation of any two diagonals of a regular pentagon belongs to family of lines and their lengths are , then locus of centre of circle circumscribing the given pentagon (the triangles formed by these diagonals with sides of pentagon have no side common) is
a)
b)
c)
d)
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If the equation of any two diagonals of a regular pentagon belongs to family of lines |
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a) |
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b) |
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c) |
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d) |
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1 Answer
127 votes
Answer Key / Explanation : (a) -
(a)
Point of intersection of diagonals lie on circumcircle
i.e. (1, 1), since 
.png)
Locus is 
127 votes
Answer Link
127