The pH of a 0.02 M NH4Cl solution will be [given Kb(NH4OH)= 10−5 and log 2 = 0.301]
Question ID - 56285 | SaraNextGen Top Answer The pH of a 0.02 M NH4Cl solution will be [given Kb(NH4OH)= 10−5 and log 2 = 0.301]
The pH of a 0.02 M NH4Cl solution will be [given Kb(NH4OH)= 10−5 and log 2 = 0.301]
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