The minimum amount of 
consumed per gram of reactant is for the reaction:
(Given atomic mass : Fe = 56, O = 16, Mg = 24, P = 31, C = 12, H = 1)
(a)
2Mg(s) + 
→2MgO(s)
(b)
4Fe(s) + 3
(g)→2F
(s)
(c)
→3C
(I)
(d)
(s)
The minimum amount of consumed per gram of reactant is for the reaction:
(Given atomic mass : Fe = 56, O = 16, Mg = 24, P = 31, C = 12, H = 1)
(a)
2Mg(s) + →2MgO(s)
(b)
4Fe(s) + 3(g)→2F(s)
(c)
→3C(I)
(d)
(s)
Question ID - 56333 | SaraNextGen Top Answer
The minimum amount of consumed per gram of reactant is for the reaction:
(Given atomic mass : Fe = 56, O = 16, Mg = 24, P = 31, C = 12, H = 1)
(a)
2Mg(s) + →2MgO(s)
(b)
4Fe(s) + 3(g)→2F(s)
(c)
→3C(I)
(d)
(s)
|
The minimum amount of (Given atomic mass : Fe = 56, O = 16, Mg = 24, P = 31, C = 12, H = 1) |
|||
|
(a) |
2Mg(s) + |
(b) |
4Fe(s) + 3 |
|
(c) |
|
(d) |
|
1 Answer
127 votes
Answer Key / Explanation : (b) -
(a) 2 Mg + 
1 g requires 
g =0.66 g of 
(b) 4Fe + 3
1 g Fe requires = 0.43 g of oxygen
(c) 
1 g of 
requires = 3.6 g of 
(d) 
1 g of P requires = 1.3 g of oxygen
127 votes
Answer Link
127