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The mole fraction of a solvent in aqueous solution of a solute is 0.8. The molality  (in mol kg−1) of the aqueous solution is :

a)

13.88 × 10−2

b)

13.88 × 10−3

c)

13.88

d)

13.88 × 10−1



Question ID - 56376 | SaraNextGen Top Answer

The mole fraction of a solvent in aqueous solution of a solute is 0.8. The molality  (in mol kg−1) of the aqueous solution is :

a)

13.88 × 10−2

b)

13.88 × 10−3

c)

13.88

d)

13.88 × 10−1

1 Answer
127 votes
Answer Key / Explanation : (c) -

Let, total 1 moles be present

nsolute = 0.2

nsolvent = 0.8 ⇒ gsolvent = 0.8 × 18

   m =

=

127 votes


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