The mole fraction of a solvent in aqueous solution of a solute is 0.8. The molality (in mol kg−1) of the aqueous solution is :
a) |
13.88 × 10−2 |
b) |
13.88 × 10−3 |
c) |
13.88 |
d) |
13.88 × 10−1 |
The mole fraction of a solvent in aqueous solution of a solute is 0.8. The molality (in mol kg−1) of the aqueous solution is :
a) |
13.88 × 10−2 |
b) |
13.88 × 10−3 |
c) |
13.88 |
d) |
13.88 × 10−1 |
Let, total 1 moles be present
nsolute = 0.2
nsolvent = 0.8 ⇒ gsolvent = 0.8 × 18
m =
=