The correct statement among the following is :

a) (SiH_{3})_{3}N is planar and less basic than (CH_{3})_{3}N

b) (SiH_{3})_{3}N is pyramidal and more basic than (CH_{3})_{3}N

c) (SiH_{3})_{3}N is pyramidal and less basic than (CH_{3})_{3}N

d) (SiH_{3})_{3}N is planar and more basic than (CH_{3})_{3}N

The correct statement among the following is :

a) (SiH_{3})_{3}N is planar and less basic than (CH_{3})_{3}N

b) (SiH_{3})_{3}N is pyramidal and more basic than (CH_{3})_{3}N

c) (SiH_{3})_{3}N is pyramidal and less basic than (CH_{3})_{3}N

d) (SiH_{3})_{3}N is planar and more basic than (CH_{3})_{3}N

1 Answer

127 votes

Trisilylamine is planar, due to backbonding of lone pairs of nitrogen into vacant d-orbitals of Si. In trimethylamine, there is no such delocalisation and hence it is more basic.

127 votes

127