The correct statement among the following is :
a) (SiH3)3N is planar and less basic than (CH3)3N
b) (SiH3)3N is pyramidal and more basic than (CH3)3N
c) (SiH3)3N is pyramidal and less basic than (CH3)3N
d) (SiH3)3N is planar and more basic than (CH3)3N
Question ID - 56405 | SaraNextGen Top Answer The correct statement among the following is :
a) (SiH3)3N is planar and less basic than (CH3)3N
b) (SiH3)3N is pyramidal and more basic than (CH3)3N
c) (SiH3)3N is pyramidal and less basic than (CH3)3N
d) (SiH3)3N is planar and more basic than (CH3)3N
The correct statement among the following is :
a) (SiH3)3N is planar and less basic than (CH3)3N
b) (SiH3)3N is pyramidal and more basic than (CH3)3N
c) (SiH3)3N is pyramidal and less basic than (CH3)3N
d) (SiH3)3N is planar and more basic than (CH3)3N
1 Answer
127 votes
Answer Key / Explanation : (a) -
Trisilylamine is planar, due to backbonding of lone pairs of nitrogen into vacant d-orbitals of Si. In trimethylamine, there is no such delocalisation and hence it is more basic.
127 votes
Answer Link
127