A solution is prepared by dissolving 0.6 g of urea (molar mass = 60 g mol−1) and 1.8 g of glucose (molar mass = 180 g mol−1) in 100 mL of water at 27°C. The osmotic pressure of the solution is (R = 0.08206 L atm K−1 mol−1)
a)
1.64 atm
b)
2.46 atm
c)
8.2 atm
d)
4.92 atm
a)
1.64 atm
b)
2.46 atm
c)
8.2 atm
d)
4.92 atm
Question ID - 56444 | SaraNextGen Top Answer A solution is prepared by dissolving 0.6 g of urea (molar mass = 60 g mol−1) and 1.8 g of glucose (molar mass = 180 g mol−1) in 100 mL of water at 27°C. The osmotic pressure of the solution is (R = 0.08206 L atm K−1 mol−1)
a)
1.64 atm
b)
2.46 atm
c)
8.2 atm
d)
4.92 atm
A solution is prepared by dissolving 0.6 g of urea (molar mass = 60 g mol−1) and 1.8 g of glucose (molar mass = 180 g mol−1) in 100 mL of water at 27°C. The osmotic pressure of the solution is (R = 0.08206 L atm K−1 mol−1)
|
a) |
1.64 atm |
b) |
2.46 atm |
|
c) |
8.2 atm |
d) |
4.92 atm |
1 Answer
127 votes
Answer Key / Explanation : (d) -
Osmotic pressure (
) = CRT
Solute : urea and glucose
= (C1 + C2) RT
=
=0.2
0.0821
300
= 4.926 atm
127 votes
Answer Link
127