For x^{2} n +1 N(the set of natural numbers), the integral is equal to (Where c is a constant of integration)

a. |
log |
b. |
log |

c. |
log |
d. |
log |

For x^{2} n +1 N(the set of natural numbers), the integral is equal to (Where c is a constant of integration)

a. |
log |
b. |
log |

c. |
log |
d. |
log |

1 Answer

127 votes

Put (x^{2}−1)=I

2xdx = dt

∴ I = dt

=

= ln c

= ln +c

127 votes

127