The equation of the plane containing the straight line 
= 
=
and perpendicular to the place containing the straight lines 
= 
= 
and 
= 
= 
is
a.
x+2y−2z = 0
b.
x−2y+z=0
c.
5x+2y−4z = 0
d.
3x+2y−3z=0
= = and perpendicular to the place containing the straight lines = = and = = isa.
x+2y−2z = 0
b.
x−2y+z=0
c.
5x+2y−4z = 0
d.
3x+2y−3z=0
Question ID - 56753 | SaraNextGen Top Answer The equation of the plane containing the straight line = = and perpendicular to the place containing the straight lines = = and = = is
a.
x+2y−2z = 0
b.
x−2y+z=0
c.
5x+2y−4z = 0
d.
3x+2y−3z=0
The equation of the plane containing the straight line = = and perpendicular to the place containing the straight lines = = and = = is
|
a. |
x+2y−2z = 0 |
b. |
x−2y+z=0 |
|
c. |
5x+2y−4z = 0 |
d. |
3x+2y−3z=0 |
1 Answer
127 votes
Answer Key / Explanation : (b) -
Vector along the normal to the plane containing the lines
= 
= 
and 
= 
= 
is (8
−10
)
Vector perpendicular to the vectors 2
+3
+4
and 8
10
is 26
−52
+26
So, required plane is
26x−52y+26z=0
x−2y+z=0
127 votes
Answer Link
127