Let f : R→R be a function such that f(x) =   Then f(2) equal
(a)	8	(b)	2
(c)	4	(d)	30

f(x) =

⇒  (x) = 3        ……(1)

⇒  = 6x + 2(1)                             ……(2)

⇒  (x) =6                                                 …...(3)

put x = 1 in equation (1) :

 (1) = 3 + 2 (1) +  (2)                          …..(4)

put x = 2 in equation (2) :

 (2) = 12 + 2 (1)                                      …..(5)

from equation (4) & (5) :

3  (1) = 12 + 2(1)

⇒3(1) = 15

⇒(1) = 5  ⇒   (2) = 2                          ….(6)

Put x = 3 in equation (3) :

 (3) = 6

  f(x) =

f(2) = 8 20 +4 +6 = −2.