Let d and A =, If the minimum value of det(A) is 8, then a value of d is |
|||
(a) |
7 |
(b) |
2 |
(c) |
5 |
(d) |
2 |
Let d and A =, If the minimum value of det(A) is 8, then a value of d is |
|||
(a) |
7 |
(b) |
2 |
(c) |
5 |
(d) |
2 |
detA =
(
=
=(2+sin
= 4 + 4d 2sin
=
= (d +2
For a given d, minimum value of
det(A) = (d +2
⇒ d = 1 or 5