If the third term in the binomial expansion of (1 + 
equals 2560, then a possible value of x is :
(a)
2
(b)
(c)
4
(d)
If the third term in the binomial expansion of (1 + equals 2560, then a possible value of x is :
(a)
2
(b)
(c)
4
(d)
Question ID - 56818 | SaraNextGen Top Answer
If the third term in the binomial expansion of (1 + equals 2560, then a possible value of x is :
(a)
2
(b)
(c)
4
(d)
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If the third term in the binomial expansion of (1 + |
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(a) |
2 |
(b) |
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(c) |
4 |
(d) |
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1 Answer
127 votes
Answer Key / Explanation : (d) -
(1 + 
5
⇒ 10.
⇒ 
⇒ 2(lo
⇒ 2(log2x)2 = 8
⇒ (log2x)2 = 4
x = 4 or 
127 votes
Answer Link
127