If the line 3x + 4y − 24 = 0 intersects the x-axis at the point A and the y-axis at the point B, then the incentre of the triangle OAB, where O is the origin, is
(a)
(3, 4)
(b)
(2, 2)
(c)
(4, 4)
(d)
(4, 3)
If the line 3x + 4y − 24 = 0 intersects the x-axis at the point A and the y-axis at the point B, then the incentre of the triangle OAB, where O is the origin, is
(a)
(3, 4)
(b)
(2, 2)
(c)
(4, 4)
(d)
(4, 3)
Question ID - 56841 | SaraNextGen Top Answer
If the line 3x + 4y − 24 = 0 intersects the x-axis at the point A and the y-axis at the point B, then the incentre of the triangle OAB, where O is the origin, is
(a)
(3, 4)
(b)
(2, 2)
(c)
(4, 4)
(d)
(4, 3)
|
If the line 3x + 4y − 24 = 0 intersects the x-axis at the point A and the y-axis at the point B, then the incentre of the triangle OAB, where O is the origin, is |
|||
|
(a) |
(3, 4) |
(b) |
(2, 2) |
|
(c) |
(4, 4) |
(d) |
(4, 3) |
1 Answer
127 votes
Answer Key / Explanation : (b) -
7r – 24 = 
2r = 24 or 12r + 24
r= 14, r = 2
then incentre is (2, 2)
127 votes
Answer Link
127