Two sides of a parallelogram are along the lines, x+y=3 and x−y+3=0. If its diagonals intersect at (2, 4), then one of its vertex is : |
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(a) |
(2, 6) |
(b) |
(2, 1) |
(c) |
(3, 5) |
(d) |
(3, 6) |
Two sides of a parallelogram are along the lines, x+y=3 and x−y+3=0. If its diagonals intersect at (2, 4), then one of its vertex is : |
|||
(a) |
(2, 6) |
(b) |
(2, 1) |
(c) |
(3, 5) |
(d) |
(3, 6) |
x_{1 }=4 similarly y_{1}=5
C⇒(4, 5)
Now equation of BC is x−y=−1
and equation of CD is x+y=9
solving x+y=9 and x−y=−3
point D is (3, 6)
option (d)