Let f(x)= and g(x)=|f(x)|+f(|x|). Then, in the interval (−2, 2), g is |
|||
(a) |
Differentiable at all points |
(b) |
Not differentiable at two points |
(c) |
Not continuous |
(d) |
Not differentiable at one point |
Let f(x)= and g(x)=|f(x)|+f(|x|). Then, in the interval (−2, 2), g is |
|||
(a) |
Differentiable at all points |
(b) |
Not differentiable at two points |
(c) |
Not continuous |
(d) |
Not differentiable at one point |
|f(x)|=
And f(|x|)=x2−1, x∈[−2, 2]
Hence g(x)=
t is not differentiable at x=1