Let f(x)= and g(x)=|f(x)|+f(|x|). Then, in the interval (−2, 2), g is |
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(a) |
Differentiable at all points |
(b) |
Not differentiable at two points |

(c) |
Not continuous |
(d) |
Not differentiable at one point |

Let f(x)= and g(x)=|f(x)|+f(|x|). Then, in the interval (−2, 2), g is |
|||

(a) |
Differentiable at all points |
(b) |
Not differentiable at two points |

(c) |
Not continuous |
(d) |
Not differentiable at one point |

1 Answer

127 votes

|f(x)|=

And f(|x|)=x^{2}−1, x∈[−2, 2]

Hence g(x)=

t is not differentiable at x=1

127 votes

127