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If y(x) is the solution of the different equation y=e−2x, x>0

Where y(1)=e12, then   

(a)

y(x) is decreasing in(0, 1)

(b)

y(x) is decreasing in

(c)

y(loge2)=

(d)

y (loge2)=loge4


Question ID - 56999 | Toppr Answer

If y(x) is the solution of the different equation y=e−2x, x>0

Where y(1)=e12, then   

(a)

y(x) is decreasing in(0, 1)

(b)

y(x) is decreasing in

(c)

y(loge2)=

(d)

y (loge2)=loge4

1 Answer - 5876 Votes

3537

Answer Key : (b) -

=e−2x

I.F=e2x+nx=e2x.x

So, y(xe2x)=2x+c

⇒xye2x= dx+c

⇒2xye2x=x2+2c

It passes throughwe get c=0

y=

 (−2x+1)

⇒f(x)is decreasing in

y(loge2)=

=loge2



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