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If one real root of the quadratic equation 81x2+kx+256=0 is cube of the other root, then a value of k is

(a)

−81

(b)

100

(c)

−300

(d)

144


Question ID - 57001 | Toppr Answer

If one real root of the quadratic equation 81x2+kx+256=0 is cube of the other root, then a value of k is

(a)

−81

(b)

100

(c)

−300

(d)

144

1 Answer - 5876 Votes

3537

Answer Key : (c) -

81x2+kx+256=0 ;x=

==

Now =

⇒k=



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