The solution of the differential equation. 
= (x − y)2, when y(1) = 1, is
a.
loge
b.
loge
x − y
c.
−loge
= x+y − 2
d.
−loge
=2(x − 1 )
= (x − y)2, when y(1) = 1, isa.
loge
b.
loge x − y
c.
−loge = x+y − 2
d.
−loge =2(x − 1 )
Question ID - 57141 | SaraNextGen Top Answer The solution of the differential equation. = (x − y)2, when y(1) = 1, is
a.
loge
b.
loge x − y
c.
−loge = x+y − 2
d.
−loge =2(x − 1 )
The solution of the differential equation. = (x − y)2, when y(1) = 1, is
|
a. |
loge |
b. |
loge |
|
c. |
−loge |
d. |
−loge |
1 Answer
127 votes
Answer Key / Explanation : (d) -
x − y = t ⇒ 
= 1
-
⇒ 1
= t2
⇒ 
= 
= x + 
⇒
x + 
given y(1) = 1
⇒ 
(1) = 1+ 
⇒ 
= −1
⇒ 
=2(x −1)
⇒ 
=2(x −1)
127 votes
Answer Link
127