If in a parallelogram ABDC, the coordinates of A, B and C are respectively (1, 2) (3, 4) and (2, 5), Then the equation of the diagonal AD is
|
a. |
5x+3y−11 =0 |
b. |
3x−5y+7 =0 |
|
c. |
3x+5y−13=0 |
d. |
5x−3y+1=0 |
If in a parallelogram ABDC, the coordinates of A, B and C are respectively (1, 2) (3, 4) and (2, 5), Then the equation of the diagonal AD is
|
a. |
5x+3y−11 =0 |
b. |
3x−5y+7 =0 |
|
c. |
3x+5y−13=0 |
d. |
5x−3y+1=0 |
Co-ordinates of point D are (4, 7)
⇒ line AD is 5x − 3y +1=0