If in a parallelogram ABDC, the coordinates of A, B and C are respectively (1, 2) (3, 4) and (2, 5), Then the equation of the diagonal AD is

a. |
5x+3y−11 =0 |
b. |
3x−5y+7 =0 |

c. |
3x+5y−13=0 |
d. |
5x−3y+1=0 |

If in a parallelogram ABDC, the coordinates of A, B and C are respectively (1, 2) (3, 4) and (2, 5), Then the equation of the diagonal AD is

a. |
5x+3y−11 =0 |
b. |
3x−5y+7 =0 |

c. |
3x+5y−13=0 |
d. |
5x−3y+1=0 |

1 Answer

127 votes

Co-ordinates of point D are (4, 7)

⇒ line AD is 5x − 3y +1=0

127 votes

127