Let sn = 1 + q + q2 + …+qn and Tn = 1 + where q is a real number and q
1. If 101C1+101C2S1+ …… +101C101S100 =
T100, then
is equal to
a. |
2100 |
b. |
200 |
c. |
299 |
d. |
202 |
Let sn = 1 + q + q2 + …+qn and Tn = 1 + where q is a real number and q
1. If 101C1+101C2S1+ …… +101C101S100 =
T100, then
is equal to
a. |
2100 |
b. |
200 |
c. |
299 |
d. |
202 |
101C1+101C2S1+ …… +101C101S100 = T100
101C1+101C2(1+q) + 101C3(1+q+q2) + … +101C101(1+q+…+q100)
= 2
⇒ 101C1(1 − q ) +101C2(1 − q2 )+ …. + 101C101(1 − q 101)
= 2
= (2101−1) − ((1+q)101−1)
= 2
⇒ 2101 = 2
⇒ = 2100