For x >1, if (2x)2y = 4e2x−2y, then (1+loge2x )2
is equal to
a.
loge2x
b.
c.
x loge2x
d.
is equal toa.
loge2x
b.
c.
x loge2x
d.
Question ID - 57182 | SaraNextGen Top Answer For x >1, if (2x)2y = 4e2x−2y, then (1+loge2x )2 is equal to
a.
loge2x
b.
c.
x loge2x
d.
For x >1, if (2x)2y = 4e2x−2y, then (1+loge2x )2 is equal to
|
a. |
loge2x |
b. |
|
|
c. |
x loge2x |
d. |
|
1 Answer
127 votes
Answer Key / Explanation : (d) -
(2x)2y = 4e2x−2y
2y
2x = 
4 + 2x − 2y
y =
y’ = 
y’ 
= 
127 votes
Answer Link
127